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4.905x^2-5x-10=0
a = 4.905; b = -5; c = -10;
Δ = b2-4ac
Δ = -52-4·4.905·(-10)
Δ = 221.2
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-\sqrt{221.2}}{2*4.905}=\frac{5-\sqrt{221.2}}{9.81} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+\sqrt{221.2}}{2*4.905}=\frac{5+\sqrt{221.2}}{9.81} $
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